New England Patriots All-Pro TE Rob Gronkowski Gets $54 Million Deal
All-Pro tight-end Rob Gronkowski agreed Friday to a six-year, $54 million deal with the New England Patriots, making him the highest-paid player ever at his position.
The six-year deal includes $18.17 million guaranteed.
”This is a rare deal,” said Drew Rosenhaus, Gronkowski’s agent. ”Thanks to Mr. Kraft and Coach Belichick.”
Gronkowski set a league record for the position with 17 touchdowns in 2011. He also had a record 1,327 yards on 90 receptions.
He was selected in the second round of the 2010 draft and still had two years left on his contract, but New England recognized his unique skill set and locked him up through the 2019 season.
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